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If the points P(3,μ,6),Q(−1,−1,2)P(3,\mu,6), Q(-1,-1,2) and R(2,8,5)R(2,8,5) are collinear, then the value of 'μ\mu' is

Solution

✅ Correct Option: 3

Take QP⃗=(4,μ+1,4)\vec{QP} = (4,\mu+1,4) and QR⃗=(3,9,3)\vec{QR} = (3,9,3).

For collinearity these must be proportional, so 43=μ+19=43\dfrac{4}{3} = \dfrac{\mu+1}{9} = \dfrac{4}{3}.

Thus μ+1=12\mu+1 = 12, giving μ=11\mu = 11.

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