If $A = \begin{bmatrix} -2 & 1 \\ 3 & 2 \end{bmatrix}$ and $B' = \begin{bmatrix} -1 & 1 \\ 0 & 2 \end{bmatrix}$, then $(A+2B)' =$

Let $P = \begin{bmatrix} 5 & 2 \\ 7 & 4 \end{bmatrix}$, $Q = \begin{bmatrix} 2 & 5 \\ 3 & 8 \end{bmatrix}$, $R = \begin{bmatrix} 2 & -1 \\ 3 & 4 \end{bmatrix}$, then the matrix S such that QS - RP = 0 will be :

Matrix $A = \begin{bmatrix} 0 & a & 5 \\ 4 & b & -1 \\ c & 1 & 0 \end{bmatrix}$ is skew - symmetric, then the values of a, b c are :

Let X & Y be 2 invertible square matrix, then which of the following is true

(A) $(AB)^{-1} = A^{-1} B^{-1}$

(B) $(AB)^{-1} = B^{-1} A^{-1}$

(C) $(AB)' = A' B'$

(D) $(AB)' = B' A'$

Choose the answer from the options given below

If $P = \begin{bmatrix} -2 & 2 & 0 \\ 3 & 1 & 4 \end{bmatrix}$ and $Q = \begin{bmatrix} 2 & 0 & -2 \\ 7 & 1 & 6 \end{bmatrix}$, If $5Q - 3P + 2R = 0$, then the matrix R is

If a matrix A is both symmetric and skew symmetric then :

Match List I with List II

Choose the correct answer from the options given below: