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If the area(in square units) bounded by the curves y2=4xy^2 = 4x and y=xy = x is k33\dfrac{k^3}{3}, then the value of kk is:

Solution

✅ Correct Option: 2

The curves meet where x2=4xx^2 = 4x, i.e. at x=0x=0 and x=4x=4.

Area =∫04(2x−x)dx=323−8=83= \int_0^4(2\sqrt{x}-x)dx = \dfrac{32}{3}-8 = \dfrac{8}{3}.

Equating to k33\dfrac{k^3}{3} gives k3=8k^3 = 8, so k=2k = 2.

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