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For the function f(x)=3x4+4x3−12x2+12f(x) = 3x^4 + 4x^3 - 12x^2 + 12, then

Match the LIST-I with LIST-II

LIST-ILIST-II
A.x=0x = 0I.Local minimum value of f(x)f(x)
B.x=−2x = -2II.Local maximum of value of f(x)f(x)
C.f(0)f(0)III.Point of local minima
D.f(1)f(1)IV.Point of local maxima

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

f′(x)=12x(x+2)(x−1)f'(x) = 12x(x+2)(x-1), so critical points are x=−2,0,1x=-2,0,1.

The sign of f′f' goes negative, positive, negative, positive across these points. Hence x=−2x=-2 and x=1x=1 are points of local minima, and x=0x=0 is a point of local maxima.

So f(0)=12f(0)=12 is a local maximum value and f(1)=7f(1)=7 is a local minimum value.

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