Skip to main contentSkip to solution

If a⃗=5i^−j^−3k^\vec{a} = 5\hat{i} - \hat{j} - 3\hat{k} and b⃗=i^−3j^−5k^\vec{b} = \hat{i} - 3\hat{j} - 5\hat{k} then (a⃗+b⃗).(a⃗−b⃗)(\vec{a}+\vec{b}).(\vec{a}-\vec{b}) is equal to:

Solution

✅ Correct Option: 2

Use the identity (a⃗+b⃗)⋅(a⃗−b⃗)=∣a⃗∣2−∣b⃗∣2(\vec{a}+\vec{b})\cdot(\vec{a}-\vec{b}) = |\vec{a}|^2-|\vec{b}|^2.

Here ∣a⃗∣2=25+1+9=35|\vec{a}|^2 = 25+1+9 = 35 and ∣b⃗∣2=1+9+25=35|\vec{b}|^2 = 1+9+25 = 35.

Hence the value is 35−35=035-35 = 0.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question