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If the matrix [0α22β1γ−10]\begin{bmatrix}0 & \alpha & 2\\2 & \beta & 1\\\gamma & -1 & 0\end{bmatrix} is skew-symmetric, then (β−α−γ)(\beta-\alpha-\gamma) equals

Solution

✅ Correct Option: 3

Skew symmetry requires zero diagonal, so β=0\beta=0; also a12=−a21a_{12}=-a_{21} gives α=−2\alpha=-2, and a13=−a31a_{13}=-a_{31} gives γ=−2\gamma=-2. Hence β−α−γ=0+2+2=4\beta-\alpha-\gamma=0+2+2=4.

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