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Area of the bounded region between the curve y=∣x−2∣y = |x - 2| and the line y=2y = 2 is:

Solution

✅ Correct Option: 2

The curve y=∣x−2∣y = |x - 2| is V-shaped with vertex at (2,0)(2, 0).

When x≥2x \geq 2: y=x−2y = x - 2

When x<2x < 2: y=2−xy = 2 - x


To find intersection points, solve ∣x−2∣=2|x - 2| = 2:

For x≥2x \geq 2:

x−2=2x - 2 = 2

x=4x = 4

For x<2x < 2:

2−x=22 - x = 2

x=0x = 0

Intersection points are (0,2)(0, 2) and (4,2)(4, 2).


The bounded region forms a triangle with:

  • Vertices at (0,2)(0, 2), (4,2)(4, 2), and (2,0)(2, 0)
  • Base = 4−0=44 - 0 = 4 units
  • Height = 2−0=22 - 0 = 2 units

Area =12×base×height= \dfrac{1}{2} \times \text{base} \times \text{height}

Area =12×4×2= \dfrac{1}{2} \times 4 \times 2

Area =4= 4

Therefore, the area of the bounded region is 44 square units.

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