The area bounded by x = sqrt(9 - y^2), x - y + 3 = 0 and x-axis is : Option 1: 9/4( - 2) sq. units Option 2: 9/2( + 1) sq. units Option 3: 9/4( + 2) sq. units Option 4: 9/2( + 2) sq. units

The answer is '9/4( + 2) sq. units'. View full solution:

CUET Mathematics - The area bounded by x = sqrt(9 - y^2), x - y + 3 = 0 and x-axis is : | PYQs + Solutions

CUET Mathematics 2022 7 Aug Shift 2

Calculus

Hard

$\frac{9}{4}(\pi - 2)$ sq. units

$\frac{9}{2}(\pi + 1)$ sq. units

$\frac{9}{4}(\pi + 2)$ sq. units

$\frac{9}{2}(\pi + 2)$ sq. units

✅ Correct Option: 3