The particular solution of the differential equation dy=e^2x+ydx, y(0)=0 is Option 1: x=_e|3+e^2y2| Option 2: x=_e|3-e^2y2| Option 3: y=_e|23-e^2x| Option 4: y=_e|23+e^2x|

The answer is 'y=_e|23-e^2x|'. View full solution:

CUET Mathematics - The particular solution of the differential equation dy=e^2x+ydx, y(0)=0 is | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 1

Calculus

Medium

common

$x=\log_e\left|\frac{3+e^{2y}}{2}\right|$

$x=\log_e\left|\frac{3-e^{2y}}{2}\right|$

$y=\log_e\left|\frac{2}{3-e^{2x}}\right|$

$y=\log_e\left|\frac{2}{3+e^{2x}}\right|$

✅ Correct Option: 3

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Choose the correct answer from the options given below:

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