The value of vmatrix 0 & xy^2 & xz^2 \\ x^2y & 0 & yz^2 \\ x^2z & zy^2 & 0 vmatrix is: Option 1: 0 Option 2: x^3y^3z^3 Option 3: 2x^3y^3z^3 Option 4: -2x^3y^3z^3

The answer is '2x^3y^3z^3'. View full solution:

CUET Mathematics - The value of vmatrix 0 & xy^2 & xz^2 \\ x^2y & 0 & yz^2 \\ x^2z & zy^2 & 0 vmatrix is: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 1

Algebra

Medium

common

$x^3y^3z^3$

$2x^3y^3z^3$

$-2x^3y^3z^3$

✅ Correct Option: 3

Related questions:

15 May Shift 2

Match List-I with List-II

List-I	List-II
(Matrix A)	(Determinant of adj A)
(A) $\begin{bmatrix} 2 & 1 \\ 0 & -1 \end{bmatrix}$	(I) 6
(B) $\begin{bmatrix} 0 & 1 \\ 4 & -1 \end{bmatrix}$	(II) 5
(C) $\begin{bmatrix} 1 & 2 \\ -3 & -1 \end{bmatrix}$	(III) -4
(D) $\begin{bmatrix} 4 & -2 \\ 3 & 0 \end{bmatrix}$	(IV) -2

Choose the correct answer from the options given below:

15 May Shift 2

If A is a matrix of order $m × n$ and $B$ is a matrix such that $AB^T$ and $B^TA$ are both well-defined matrices, then order of matrix B is

22 May Shift 1

If $\begin{bmatrix} 1 & 3 \\ 2 & 4 \end{bmatrix} \begin{bmatrix} 3 & 5 \\ -1 & 3 \end{bmatrix} = \begin{bmatrix} m & 14 \\ 2 & n \end{bmatrix}$ , then $m + n$ is equal to

CUET Mathematics 2026 22nd May Shift 1 PYQs

Keyboard Shortcuts