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The value of ∣0xy2xz2x2y0yz2x2zzy20∣\begin{vmatrix} 0 & xy^2 & xz^2 \\ x^2y & 0 & yz^2 \\ x^2z & zy^2 & 0 \end{vmatrix} is:

Solution

✅ Correct Option: 3

Expanding along the first row gives −xy2(x2y⋅0−yz2⋅x2z)+xz2(x2y⋅zy2−0)-xy^2\left(x^2y\cdot0-yz^2\cdot x^2z\right)+xz^2\left(x^2y\cdot zy^2-0\right).

This equals x3y3z3+x3y3z3=2x3y3z3x^3y^3z^3+x^3y^3z^3=2x^3y^3z^3.

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