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Match List-I with List-II

List-I (Lines)List-II (Direction Ratios)
(A) 2x+3=y+1=z−12x+3=y+1=z-1(I) -1, 2, 0
(B) 1−2x2=y2,z=2\frac{1-2x}{2}=\frac{y}{2}, z=2(II) 1, 1, 1
(C) x=3y−13=z+1x=\frac{3y-1}{3}=z+1(III) 2, 1, 1
(D) x=2y+3,z=y+1x=2y+3, z=y+1(IV) 1, 2, 2

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

(A) becomes x+3/21/2=y+11=z−11\frac{x+3/2}{1/2}=\frac{y+1}{1}=\frac{z-1}{1}, ratios (1,2,2)(1,2,2), so (IV).

(B) becomes x−1/2−1=y2\frac{x-1/2}{-1}=\frac{y}{2} with zz constant, ratios (−1,2,0)(-1,2,0), so (I).

(C) is x=y−13=z+1x=y-\frac{1}{3}=z+1, ratios (1,1,1)(1,1,1), so (II). In (D), putting y=ty=t gives ratios (2,1,1)(2,1,1), so (III).

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