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If the lines 1−x2=2yp=z−11\frac{1-x}{2}=\frac{2y}{p}=\frac{z-1}{1} and 3−2xp=y−12=z1\frac{3-2x}{p}=\frac{y-1}{2}=\frac{z}{1} are parallel then value of 'p' is

Solution

✅ Correct Option: 2

Written symmetrically, the first line has direction ratios (−2,p2,1)\left(-2,\frac{p}{2},1\right) and the second has (−p2,2,1)\left(-\frac{p}{2},2,1\right).

For parallel lines these are proportional; the third components are equal, so p2=2\frac{p}{2}=2 and −2=−p2-2=-\frac{p}{2} both give p=4p=4.

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