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General solution of the differential equation dydx=ex22+xy\frac{dy}{dx}=e^{\frac{x^2}{2}}+xy is: (where C is an arbitrary constant)

Solution

✅ Correct Option: 4

Rewrite as dydx−xy=ex2/2\frac{dy}{dx}-xy=e^{x^2/2}, a linear equation with integrating factor e−x2/2e^{-x^2/2}.

Then ddx(ye−x2/2)=1\frac{d}{dx}\left(ye^{-x^2/2}\right)=1, so ye−x2/2=x+Cye^{-x^2/2}=x+C and y=(x+C)ex2/2y=(x+C)e^{x^2/2}.

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