Arithmetic

Time, Speed & Distance

Hard

applied

In a kilometer race, A beats B by 30 seconds and B beats C by 15 seconds. If A beats C by 180 m, then

Match List-I with List-II

List-I List-II
(A) Time taken by A to run 1 km (I) 250 seconds
(B) Time taken by B to run 1 km (II) 45 seconds
(C) Time taken by C to run 1 km (III) 235 seconds
(D) A beats C by (IV) 205 seconds

Choose the correct answer from the options given below:

List-I	List-II
(A) Time taken by A to run 1 km	(I) 250 seconds
(B) Time taken by B to run 1 km	(II) 45 seconds
(C) Time taken by C to run 1 km	(III) 235 seconds
(D) A beats C by	(IV) 205 seconds

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (II), (B) - (IV), (C) - (I), (D) - (III)

✅ Correct Option: 2

A beats C by $30+15=45$ seconds, and C covers the last $180$ m in that time, so C's speed is $4$ m/s and C needs $250$ s for $1$ km.

Then B takes $250-15=235$ s and A takes $235-30=205$ s.

So (A)-(IV), (B)-(III), (C)-(I), and A beats C by $45$ seconds, (D)-(II).

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Solution

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