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If y=eπxy=e^{\pi x} and t=xπt=x^{\pi}, then which of following statements is/are TRUE ?

(A) d2ydt2=yt2(π(x−1)+1π)x\frac{d^2y}{dt^2}=\frac{y}{t^2}\left(\frac{\pi(x-1)+1}{\pi}\right)x

(B) d2ydt2=y(π(x−1)+1π)x\frac{d^2y}{dt^2}=y\left(\frac{\pi(x-1)+1}{\pi}\right)x

(C) d2ydt2=1\frac{d^2y}{dt^2}=1 at x=1x=1

(D) d2ydt2=eππ\frac{d^2y}{dt^2}=\frac{e^{\pi}}{\pi} at x=1x=1

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

dydt=πeπxπxπ−1=eπxx1−π\frac{dy}{dt}=\frac{\pi e^{\pi x}}{\pi x^{\pi-1}}=e^{\pi x}x^{1-\pi}.

Differentiating again with respect to tt means dividing by dtdx=πxπ−1\frac{dt}{dx}=\pi x^{\pi-1}, giving d2ydt2=eπx(πx−π+1)πx2π−1\frac{d^2y}{dt^2}=\frac{e^{\pi x}\left(\pi x-\pi+1\right)}{\pi x^{2\pi-1}}, which is exactly the expression in (A).

At x=1x=1 this equals eππ\frac{e^{\pi}}{\pi}, so (D) is true and (C) is false.

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