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The general solution of the differential equation x(x2−1)dydx=1x(x^2-1)\frac{dy}{dx} = 1 is:

[Where C is an arbitrary constant]

Solution

✅ Correct Option: 1

dy=dxx(x2−1)dy=\frac{dx}{x(x^2-1)}. Partial fractions give 1x(x−1)(x+1)=−1x+12(x−1)+12(x+1)\frac{1}{x(x-1)(x+1)}=-\frac1x+\frac{1}{2(x-1)}+\frac{1}{2(x+1)}.

Integrating: y=−log⁡∣x∣+12log⁡∣x2−1∣+C=12log⁡e∣x2−1x2∣+Cy=-\log|x|+\frac12\log|x^2-1|+C=\frac12\log_e\left|\frac{x^2-1}{x^2}\right|+C.

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