CUET Mathematics - Match List-I with List-II (Consider _e x = x) | List-I | List-II | |---|---| | **Integral** | **Solution: where C is an arbitrary constant** | | (A) f'(x)/f(x) f(x) dx | (I) x( x) + c | | (B) (( x) + 1/ x) dx | (II) x/ x + C | | (C) x/(1+ x)^2 dx | (III) (f(x)) + c | | (D) (1/ x - 1/( x)^2) dx | (IV) x/1+ x + c | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 1

Calculus

Medium

common

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (III), (B) - (II), (C) - (IV), (D) - (I)

✅ Correct Option: 3

Related questions:

21 May Shift 1

Match List-I with List-II (Given that $c$ is an arbitrary constant)

List-I	List-II
(A) $\int \frac{dx}{\sqrt{a^2 - x^2}} =$	(I) $\log_e \vert x + \sqrt{x^2 - a^2}\vert + c$
(B) $\int \sqrt{a^2 - x^2} dx =$	(II) $\sin^{-1} \frac{x}{a} + c$
(C) $\int \sqrt{x^2 - a^2} dx =$	(III) $\frac{x}{2} \sqrt{a^2 - x^2} + \frac{a^2}{2} \sin^{-1} \frac{x}{a} + c$
(D) $\int \frac{dx}{\sqrt{x^2 - a^2}} =$	(IV) $\frac{x}{2} \sqrt{x^2 - a^2} - \frac{a^2}{2} \log_e \vert x + \sqrt{x^2 - a^2}\vert + c$

Choose the correct answer from the options given below:

26 May Shift 2

$\int \frac{(x-1)e^x}{x^2} dx, x > 0$ equals (where C is an arbitrary constant)

15 May Shift 1

For $x \in \left(0, \frac{\pi}{2}\right)$ , $\int \frac{1}{\sin^2 x + \sin 2x} dx$ is equal to

CUET Mathematics 2026 22nd May Shift 1 PYQs