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If y=xdydx+a2(dydx)2+b2y = x\frac{dy}{dx} + \sqrt{a^2\left(\frac{dy}{dx}\right)^2 + b^2}, then the order and degree of the differential equation are

Solution

✅ Correct Option: 3

Only the first derivative appears, so the order is 1.

To find the degree, remove the radical: (y−xy′)2=a2(y′)2+b2(y-xy')^2=a^2(y')^2+b^2, i.e. y2−2xyy′+x2(y′)2=a2(y′)2+b2y^2-2xyy'+x^2(y')^2=a^2(y')^2+b^2. The highest power of y′y' is 2, so the degree is 2.

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