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Let height and radius of a right circular cylinder are hh and rr respectively. If it is open at the top, having a given surface area and greatest volume, then

Solution

✅ Correct Option: 3

With S=πr2+2πrhS=\pi r^2+2\pi rh fixed, h=S−πr22πrh=\frac{S-\pi r^2}{2\pi r} and V=πr2h=Sr−πr32V=\pi r^2h=\frac{Sr-\pi r^3}{2}.

Setting dVdr=S−3πr22=0\frac{dV}{dr}=\frac{S-3\pi r^2}{2}=0 gives S=3πr2S=3\pi r^2, and substituting back gives h=rh=r.

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