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Match List-I with List-II

List-IList-II
(A) For a random variable X, E(X)=3E(X)=3 and E(X2)=11E(X^2)=11, then Var(X)Var(X) is(I) 25
(B) For a random variable X, E(X)=3E(X)=3 and E(X2)=13E(X^2)=13, then Var(X2)Var\left(\frac{X}{2}\right) is(II) 2
(C) In a binomial distribution, if n=20,q=0.75n=20, q=0.75, then its mean is(III) 1
(D) If in a binomial distribution, mean is 5 and variance is 4, then the number of trials is(IV) 5

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

(A): Var(X)=11−9=2Var(X)=11-9=2, so (II).

(B): Var(X)=13−9=4Var(X)=13-9=4, so Var(X2)=44=1Var\left(\frac{X}{2}\right)=\frac{4}{4}=1, giving (III).

(C): p=0.25p=0.25, so mean =20(0.25)=5=20(0.25)=5, giving (IV).

(D): q=45q=\frac{4}{5} and p=15p=\frac{1}{5}, so n=51/5=25n=\frac{5}{1/5}=25, giving (I).

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