If adjA=bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix, then A^-1 is: Option 1: 1/6bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix Option 2: ±1/9bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix Option 3: ±1/9bmatrix7 & 3 & -1\\-3 & 0 & 3\\2 & -3 & 1bmatrix Option 4: 1/9bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix

The answer is '±1/9bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix'. View full solution:

CUET Mathematics - If adjA=bmatrix7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1bmatrix, then A^-1 is: | PYQs + Solutions

CUET Mathematics 2026 22nd May Shift 1

Algebra

Medium

core

$\frac{1}{6}\begin{bmatrix}7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1\end{bmatrix}$

$\pm\frac{1}{9}\begin{bmatrix}7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1\end{bmatrix}$

$\pm\frac{1}{9}\begin{bmatrix}7 & 3 & -1\\-3 & 0 & 3\\2 & -3 & 1\end{bmatrix}$

$\frac{1}{9}\begin{bmatrix}7 & -3 & 2\\3 & 0 & -3\\-1 & 3 & 1\end{bmatrix}$

✅ Correct Option: 2

Related questions:

2 June Shift 1

If $A = \begin{bmatrix}1 & 2\\ 0 & 3\end{bmatrix}$ then $|A. adj A|$ is

22 May Shift 2

Match List-I with List-II

List-I	List-II
(A) A square matrix $P$ is said to be non-singular if	(I) $\vert P\vert = 0$
(B) A square matrix $P$ is said to be singular if	(II) $P P^T$ is symmetric
(C) If a matrix $P$ is both symmetric and skew-symmetric, then	(III) $\vert P\vert \neq 0$
(D) If $P$ is a square matrix, then	(IV) $P$ is a null matrix

Choose the correct answer from the options given below:

15 May Shift 2

If $\begin{bmatrix} 1 & 0 \\ b & 5 \end{bmatrix} + 2\begin{bmatrix} a & 0 \\ 1 & -2 \end{bmatrix} = I$ , where $I$ is a unit matrix of order 2, then the value of $(a - b)$ is:

CUET Mathematics 2026 22nd May Shift 1 PYQs

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