CUET Mathematics 2026 22nd May Shift 1 PYQs

The integral $\int e^x \left(\frac{x-1}{2x^2}\right) dx$ is equal to:

$\int_0^{\pi/2} \sqrt{1 - \sin 2x}\,dx$ is equal to:

$\int_1^2 \frac{x \, dx}{(x+1)(x+2)} =$