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Let a function f:R→Rf:\mathbb{R}\to\mathbb{R} defined as f(x)=x−[x]f(x)=x-[x], (where R\mathbb{R} is set of real numbers & [.][.] denotes greatest integer function) .Then the function:

Solution

✅ Correct Option: 2

f(x)=x−[x]f(x)=x-[x] is the fractional part, which is periodic with period 11, so f(0)=f(1)=0f(0)=f(1)=0 and ff is not one-one.

Its range is [0,1)[0,1) rather than all of R\mathbb{R}, so it is not onto either.

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