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The value of ∫03x3−x+x dx\int_{0}^{3} \frac{\sqrt{x}}{\sqrt{3-x}+\sqrt{x}}\,dx is

Solution

✅ Correct Option: 3

Using ∫0af(x)dx=∫0af(a−x)dx\int_0^a f(x)dx = \int_0^a f(a-x)dx, call the integral II and add the transformed version: 2I=∫031 dx=32I = \int_0^3 1\,dx = 3. Hence I=32I = \frac{3}{2}.

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