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For 6 trials of an experiment, let X be a binomial variate which satisfies the relation 9P(X=4)=P(X=2)9P(X=4)=P(X=2), then the probability of success is

Solution

✅ Correct Option: 3

With n=6n=6, 9(64)p4q2=(62)p2q49\binom{6}{4}p^4q^2 = \binom{6}{2}p^2q^4.

Since (64)=(62)\binom{6}{4} = \binom{6}{2}, this reduces to 9p2=q29p^2 = q^2, so 3p=q=1−p3p = q = 1-p.

Hence 4p=14p = 1 and p=14p = \dfrac{1}{4}.

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