If y = sqrt(2024x + 2025), then which of the following is correct? Option 1: yd^2y/dx^2 - 2dy/dx = 0 Option 2: yd^2y/dx^2 - 2(dy/dx)^2 = 0 Option 3: yd^2y/dx^2 + x(dy/dx)^2 = 0 Option 4: yd^2y/dx^2 + (dy/dx)^2 = 0

The answer is 'yd^2y/dx^2 + (dy/dx)^2 = 0'. View full solution:

CUET Mathematics - If y = sqrt(2024x + 2025), then which of the following is correct? | PYQs + Solutions

CUET Mathematics 2025 13 May Shift 1

Calculus

Medium

applied

$y\frac{d^2y}{dx^2} - 2\frac{dy}{dx} = 0$

$y\frac{d^2y}{dx^2} - 2\left(\frac{dy}{dx}\right)^2 = 0$

$y\frac{d^2y}{dx^2} + x\left(\frac{dy}{dx}\right)^2 = 0$

$y\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 = 0$

✅ Correct Option: 4

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