Skip to main contentSkip to solution

Bag A contains 2 red and 3 white balls, Bag B contains 3 red and 2 white balls. If a ball is drawn at random and is found to be red, then the probability that it was drawn from bag B, is :

Solution

✅ Correct Option: 1

By Bayes: P(B∣red)=P(red∣B)P(B)P(red∣A)P(A)+P(red∣B)P(B)=(3/5)(1/2)(2/5)(1/2)+(3/5)(1/2)=3/105/10=35P(B|\text{red}) = \frac{P(\text{red}|B)P(B)}{P(\text{red}|A)P(A)+P(\text{red}|B)P(B)} = \frac{(3/5)(1/2)}{(2/5)(1/2)+(3/5)(1/2)} = \frac{3/10}{5/10} = \frac{3}{5}.

2022: 6 Aug Shift 2

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question