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Let A be a non-singular square matrix of order 3 and ∣adjA∣=5|adj A| = 5 then ∣A∣|A| is equal to

Solution

✅ Correct Option: 1

Given that A is a non-singular square matrix of order 3 and ∣adjA∣=5|adj A| = 5.

For any square matrix of order nn, the relationship between the determinant of a matrix and its adjoint is:

∣adjA∣=∣A∣n−1|adj A| = |A|^{n-1}


Since A is of order 3, we have n=3n = 3.

∣adjA∣=∣A∣3−1|adj A| = |A|^{3-1}

∣adjA∣=∣A∣2|adj A| = |A|^2


Substituting the given value ∣adjA∣=5|adj A| = 5:

5=∣A∣25 = |A|^2

∣A∣2=5|A|^2 = 5

∣A∣=±5|A| = \pm\sqrt{5}


Therefore, ∣A∣=±5|A| = \pm\sqrt{5}

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