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If A is a square matrix of order 3 and ∣A∣|A| is 2, then value of ∣adj(A)∣|adj(A)| is :

Solution

✅ Correct Option: 3

For a square matrix of order nn, ∣adj(A)∣=∣A∣n−1|adj(A)| = |A|^{n-1}. Here n=3n = 3 and ∣A∣=2|A| = 2, so ∣adj(A)∣=23−1=22=4|adj(A)| = 2^{3-1} = 2^2 = 4.

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