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The rate of change of volume of a sphere with respect to its surface area when radius of the sphere is 4 cm, is

Solution

✅ Correct Option: 2

V=43πr3V=\dfrac43\pi r^3, S=4πr2S=4\pi r^2.

dVdS=dV/drdS/dr=4πr28πr=r2\dfrac{dV}{dS}=\dfrac{dV/dr}{dS/dr}=\dfrac{4\pi r^2}{8\pi r}=\dfrac{r}{2}.

At r=4r=4, this equals 2.

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