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Let P=[5274]P = \begin{bmatrix} 5 & 2 \\ 7 & 4 \end{bmatrix}, Q=[2538]Q = \begin{bmatrix} 2 & 5 \\ 3 & 8 \end{bmatrix}, R=[2−134]R = \begin{bmatrix} 2 & -1 \\ 3 & 4 \end{bmatrix}, then the matrix S such that QS - RP = 0 will be :

Solution

✅ Correct Option: 4

From QS−RP=0QS - RP = 0: S=Q−1RPS = Q^{-1}RP.

RP=[2−134][5274]=[304322]RP = \begin{bmatrix} 2 & -1 \\ 3 & 4 \end{bmatrix}\begin{bmatrix} 5 & 2 \\ 7 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 0 \\ 43 & 22 \end{bmatrix}.

det⁡(Q)=16−15=1\det(Q) = 16 - 15 = 1, so Q−1=[8−5−32]Q^{-1} = \begin{bmatrix} 8 & -5 \\ -3 & 2 \end{bmatrix}.

S=Q−1(RP)=[8−5−32][304322]=[−191−1107744]S = Q^{-1}(RP) = \begin{bmatrix} 8 & -5 \\ -3 & 2 \end{bmatrix}\begin{bmatrix} 3 & 0 \\ 43 & 22 \end{bmatrix} = \begin{bmatrix} -191 & -110 \\ 77 & 44 \end{bmatrix}.

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