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The maximum value of z=4x+2yz = 4x + 2y, subjected to the constraints:

2x+3y≤182x + 3y \le 18, x+y≥5x + y \ge 5;

x,y≥0x, y \ge 0, is

Solution

✅ Correct Option: 1

Corner points of the region are (5,0)(5,0), (9,0)(9,0), (3,2)(3,2), (0,5)(0,5) and (0,6)(0,6). Values of z=4x+2yz = 4x+2y are 20, 36, 16, 10 and 12. The maximum is 36 at (9,0)(9,0).

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