sqrt(x^2 - 4x + 5) dx = Option 1: (x-2/2)sqrt(x^2 - 4x + 5) + |(x-2) + sqrt(x^2 - 4x + 5)| + C Option 2: (x-2/2)sqrt(x^2 - 4x + 5) + 1/2|(x-2) + sqrt(x^2 - 4x + 5)| + C Option 3: (x-2/2)sqrt(x^2 - 4x + 5) + 1/4|(x-2) + sqrt(x^2 - 4x + 5)| + C Option 4: (x-2/2)sqrt(x^2 - 4x + 5) + 3/4|(x-2) + sqrt(x^2 - 4x + 5)| + C

The answer is '(x-2/2)sqrt(x^2 - 4x + 5) + 1/2|(x-2) + sqrt(x^2 - 4x + 5)| + C'. View full solution:

CUET Mathematics - sqrt(x^2 - 4x + 5) dx = | PYQs + Solutions

CUET Mathematics 2022 23 Aug Shift 1

Calculus

Medium

$\left(\frac{x-2}{2}\right)\sqrt{x^2 - 4x + 5} + \log\left|(x-2) + \sqrt{x^2 - 4x + 5}\right| + C$

$\left(\frac{x-2}{2}\right)\sqrt{x^2 - 4x + 5} + \frac{1}{2}\log\left|(x-2) + \sqrt{x^2 - 4x + 5}\right| + C$

$\left(\frac{x-2}{2}\right)\sqrt{x^2 - 4x + 5} + \frac{1}{4}\log\left|(x-2) + \sqrt{x^2 - 4x + 5}\right| + C$

$\left(\frac{x-2}{2}\right)\sqrt{x^2 - 4x + 5} + \frac{3}{4}\log\left|(x-2) + \sqrt{x^2 - 4x + 5}\right| + C$

✅ Correct Option: 2