CUET Mathematics - The solution of the differential equation _e(dy/dx) = 5x + 2y is given by | PYQs + Solutions

CUET Mathematics 2025 30 May Shift 1

Calculus

Medium

common

$5e^{5x} + 2e^{-2y} + C = 0$ : C is an arbitrary constant

$2e^{5x} + 5e^{-2y} + C = 0$ : C is an arbitrary constant

$2e^{-5x} + 5e^{2y} + C = 0$ : C is an arbitrary constant

$5e^{-5x} + 2e^{2y} + C = 0$ : C is an arbitrary constant

✅ Correct Option: 2

Related questions:

3 June Shift 2

Match List-I with List-II

List-I	List-II
(A) Degree of this differential equation $\frac{d^2y}{dx^2} + 2log_e(\frac{d^2y}{dx^2}) = 0$	(I) 1
(B) Order of this differential equation $p(\frac{dy}{dx})^3 + 3y(\frac{d^2y}{dx^2})^3 = 0$	(II) 4
(C) Degree of $\frac{d^3y}{dx^3} + (\frac{d^2y}{dx})^2 = 0$	(III) not defined
(D) Order of the differential equation $2\frac{d^3y}{dx^3} + (\frac{d^2y}{dx^2})^2 = 0$	(IV) 2

Choose the correct answer from the options given below:

29 May Shift 2

Match List-I with List-II

List-I	List-II
Differential Equations	Degree/Order
(A) Degree of the differential equation $\frac{d^2x}{dx^2} + 2log_e x \cdot y = 0$	(I) 3
(B) Order of the differential equation $\frac{d^2y}{dx^2} + (\frac{dy}{dx})^2 + xy = 0$	(II) 2
(C) Degree of the differential equation $(\frac{d^3y}{dx^3})^2 + (\frac{dy}{dx})^3 + x^2y = 0$	(III) 1
(D) Order of the differential equation $\frac{d^2y}{dx^2} + y(\frac{dy}{dx})^3 = 0$	(IV) 4

Choose the correct answer from the options given below:

15 May Shift 1

For $y \neq 0$ , the particular solution of the differential equation $2ye^{xy}dx + (y - 2xe^{xy})dy = 0$ at the point (1, 1) is

CUET Mathematics 2025 30 May Shift 1 PYQs