Skip to main contentSkip to solution

Interval in which the function f(x)=2x3−3x2−12x+10f(x) = 2x^3 - 3x^2 - 12x + 10 is decreasing is :

Solution

✅ Correct Option: 3

f′(x)=6x2−6x−12=6(x−2)(x+1)f'(x)=6x^2-6x-12=6(x-2)(x+1).

f′(x)<0f'(x)<0 when (x−2)(x+1)<0(x-2)(x+1)<0, i.e., −1<x<2-1<x<2.

Hence ff is decreasing on [−1,2][-1,2].

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question