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Match List - I with List - II. Match the integrating factors :

List - I (Differential Equation)List - II (Integrating factor)
(A) dydx+3y=e−2x\frac{dy}{dx} + 3y = e^{-2x}(I) 1x\frac{1}{x}
(B) xdydx+y=3x2x\frac{dy}{dx} + y = 3x^2(II) e−xe^{-x}
(C) xdydx−y=3x2x\frac{dy}{dx} - y = 3x^2(III) xx
(D) dydx−y=x\frac{dy}{dx} - y = x(IV) e3xe^{3x}

Choose the correct answer from the options given below :

Solution

✅ Correct Option: 1

For form dydx+Py=Q\frac{dy}{dx} + Py = Q, IF = e∫P dxe^{\int P\,dx}.

(A) P=3⇒P = 3 \Rightarrow IF =e3x= e^{3x} (IV).

(B) dydx+yx=3x\frac{dy}{dx} + \frac{y}{x} = 3x, IF =x= x (III).

(C) dydx−yx=3x\frac{dy}{dx} - \frac{y}{x} = 3x, IF =1x= \frac{1}{x} (I).

(D) P=−1⇒P = -1 \Rightarrow IF =e−x= e^{-x} (II).

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