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If θ\theta is the angle between the lines L1L_1 and L2L_2, whose direction cosines are l1,m1,n1l_1, m_1, n_1 and l2,m2,n2l_2, m_2, n_2 respectively, then

Match List-I with List-II

List-IList-II
(A) cos⁡θ\cos\theta(I) l1l2+m1m2+n1n2l_1l_2+m_1m_2+n_1n_2
(B) sin⁡θ\sin\theta(II) l1l2+m1m2+n1n2=0l_1l_2+m_1m_2+n_1n_2=0
(C) L1L_1 and L2L_2 are perpendicular(III) l1l2=m1m2=n1n2\frac{l_1}{l_2}=\frac{m_1}{m_2}=\frac{n_1}{n_2}
(D) L1L_1 and L2L_2 are parallel(IV) ∑(m1n2−m2n1)2\sqrt{\sum(m_1n_2-m_2n_1)^2}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

For direction cosines, cos⁡θ=l1l2+m1m2+n1n2\cos\theta = l_1l_2+m_1m_2+n_1n_2 and sin⁡θ=∑(m1n2−m2n1)2\sin\theta = \sqrt{\sum(m_1n_2-m_2n_1)^2}. Perpendicular means the dot product is 0, and parallel means the direction cosines are proportional.

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