CUET Mathematics 2025 30 May Shift 1 PYQs

The particular solution of the differential equation $\frac{dy}{dx} = 8yx$ when $y = 1$ at $x = 0$

The solution of the differential equation $(x + 1)\frac{dy}{dx} + 1 - 2e^{-y} = 0$, $y(0) = 0$ is

The integrating factor of the differential equation, $x^2 \frac{dy}{dx} + xy = log_e x$ is equal to