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If 2P(A)=P(B)=5132P(A) = P(B) = \frac{5}{13} and P(A∣B)=25P(A|B) = \frac{2}{5}, then P(A∩B)P(A \cap B) is

Solution

✅ Correct Option: 2

Given 2P(A)=P(B)=5132P(A) = P(B) = \frac{5}{13}

From this:

P(B)=513P(B) = \frac{5}{13}

2P(A)=5132P(A) = \frac{5}{13}

P(A)=526P(A) = \frac{5}{26}

Also given: P(A∣B)=25P(A|B) = \frac{2}{5}


The conditional probability formula is:

P(A∣B)=P(A∩B)P(B)P(A|B) = \frac{P(A \cap B)}{P(B)}


Rearranging for P(A∩B)P(A \cap B):

P(A∩B)=P(A∣B)×P(B)P(A \cap B) = P(A|B) \times P(B)

P(A∩B)=25×513P(A \cap B) = \frac{2}{5} \times \frac{5}{13}

P(A∩B)=1065P(A \cap B) = \frac{10}{65}

P(A∩B)=213P(A \cap B) = \frac{2}{13}

Therefore, P(A∩B)=213P(A \cap B) = \frac{2}{13}

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