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The position vector of a point which divides the line joining the points with position vectors (a⃗−2b⃗)(\vec{a} - 2\vec{b}) and (2a⃗+b⃗)(2\vec{a} + \vec{b}) externally in the ratio 2:1, is

Solution

✅ Correct Option: 1

When a point divides the line joining points with position vectors p⃗\vec{p} and q⃗\vec{q} externally in the ratio m:nm : n, its position vector is:

r⃗=m⋅q⃗−n⋅p⃗m−n\vec{r} = \dfrac{m \cdot \vec{q} - n \cdot \vec{p}}{m - n}


Here, m=2m = 2, n=1n = 1, p⃗=a⃗−2b⃗\vec{p} = \vec{a} - 2\vec{b}, q⃗=2a⃗+b⃗\vec{q} = 2\vec{a} + \vec{b}

r⃗=2(2a⃗+b⃗)−1(a⃗−2b⃗)2−1\vec{r} = \dfrac{2(2\vec{a} + \vec{b}) - 1(\vec{a} - 2\vec{b})}{2 - 1}

=4a⃗+2b⃗−a⃗+2b⃗1= \dfrac{4\vec{a} + 2\vec{b} - \vec{a} + 2\vec{b}}{1}

=(4a⃗−a⃗)+(2b⃗+2b⃗)= (4\vec{a} - \vec{a}) + (2\vec{b} + 2\vec{b})

=3a⃗+4b⃗= 3\vec{a} + 4\vec{b}


The position vector of the required point is 3a⃗+4b⃗3\vec{a} + 4\vec{b}.

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