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Mr. X invested Rs. 4,00,000 in shares for 5 years. The value of this investment was Rs. 4,50,000 at the end of the second year, Rs. 490000 at the end of the third year and on maturity, the final value stood at Rs. 6,00,000. The compound annual growth rate of this investment is:

[Given that: (1.5)1/5=1.084](1.5)^{1/5} = 1.084]

Solution

✅ Correct Option: 1

CAGR (Compound Annual Growth Rate) tells you the single steady rate at which an investment would have grown per year, if it grew at the same rate every year from start to finish. The formula is:

CAGR=(Final ValueInitial Value)1n−1CAGR = \left(\dfrac{\text{Final Value}}{\text{Initial Value}}\right)^{\dfrac{1}{n}} - 1

where nn is the number of years.

Here, Initial Value =Rs.  4,00,000= Rs.\;4,00,000, Final Value =Rs.  6,00,000= Rs.\;6,00,000, and n=5n = 5 years.


CAGR=(6,00,0004,00,000)15−1CAGR = \left(\dfrac{6,00,000}{4,00,000}\right)^{\dfrac{1}{5}} - 1

CAGR=(1.5)15−1CAGR = (1.5)^{\frac{1}{5}} - 1


Using the hint given in the question, (1.5)1/5=1.084(1.5)^{1/5} = 1.084

CAGR=1.084−1=0.084CAGR = 1.084 - 1 = 0.084

Converting to percentage:

CAGR=0.084×100=8.4%CAGR = 0.084 \times 100 = 8.4\%

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