Skip to main contentSkip to solution

A boat takes 1 hour 30 minutes less to travel 36 km downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 km/hr, then the speed of the stream is:

Solution

✅ Correct Option: 1

Let the speed of the stream =x= x km/hr

Downstream speed =(10+x)= (10 + x) km/hr

Upstream speed =(10−x)= (10 - x) km/hr

Time difference =1= 1 hr 3030 min =32= \dfrac{3}{2} hours


Since Time =DistanceSpeed= \dfrac{\text{Distance}}{\text{Speed}}:

3610−x−3610+x=32\dfrac{36}{10 - x} - \dfrac{36}{10 + x} = \dfrac{3}{2}


Taking LCM on the left side:

36(10+x)−36(10−x)(10−x)(10+x)=32\dfrac{36(10 + x) - 36(10 - x)}{(10 - x)(10 + x)} = \dfrac{3}{2}

36×2x100−x2=32\dfrac{36 \times 2x}{100 - x^2} = \dfrac{3}{2}

72x100−x2=32\dfrac{72x}{100 - x^2} = \dfrac{3}{2}


144x=3(100−x2)144x = 3(100 - x^2)

144x=300−3x2144x = 300 - 3x^2

3x2+144x−300=03x^2 + 144x - 300 = 0

x2+48x−100=0x^2 + 48x - 100 = 0


(x+50)(x−2)=0(x + 50)(x - 2) = 0

x=−50x = -50 or x=2x = 2

Since speed cannot be negative, x=−50x = -50 is rejected.

Therefore, the speed of the stream =2= 2 km/hr.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question