Skip to main contentSkip to solution

Pure milk costs Rs. 75 per litre. A milkman adds water to 28 liters of pure milk and sells the mixture at Rs. 60 per litre. How many liters of water does he add?

Solution

✅ Correct Option: 3

The milkman has 28 liters of pure milk that costs Rs. 75 per liter. Water is free (costs Rs. 0). He adds water to the milk and sells the mixture at Rs. 60 per liter.


Pure milk cost =28×75= 28 \times 75

Cost =Rs. 2,100= \text{Rs. } 2,100

This is the money spent on the milk.


Let xx = liters of water added

After adding water:

Total mixture =28+x= 28 + x liters

Selling price =Rs. 60= \text{Rs. } 60 per liter

Total money received =(28+x)×60= (28 + x) \times 60


To recover the cost:

Money received == Money spent

(28+x)×60=2,100(28 + x) \times 60 = 2,100

28×60+x×60=2,10028 \times 60 + x \times 60 = 2,100

1,680+60x=2,1001,680 + 60x = 2,100

60x=2,100−1,68060x = 2,100 - 1,680

60x=42060x = 420

x=42060x = \dfrac{420}{60}

x=7x = 7


Therefore, the milkman adds 7 liters of water.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question