CUET Mathematics - For y ≠ 0, the particular solution of the differential equation 2ye^xydx + (y - 2xe^xy)dy = 0 at the point (1, 1) is | PYQs + Solutions

CUET Mathematics 2025 15 May Shift 1

Calculus

Hard

core

$\ln|y| + 2(e^{xy} - e) = 0$

$\ln|y| - 2(e^{xy} - e) = 0$

$\ln|y| + \frac{1}{2}(e^{xy} - e) = 0$

$\ln|y| - \frac{1}{2}(e^{xy} - e) = 0$

✅ Correct Option: 1

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CUET Mathematics 2025 15 May Shift 1 PYQs