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A person has purchased a home for Rs.10,00,000 with down payment of Rs 2,00,000. He amortize the balance at 9% per annum compounded monthly for 25 years then the equal monthly installment (EMI) is:

[Given that: (1.0075)300−1(.0075)(1.0075)300=119.1616]\frac{(1.0075)^{300} - 1}{(.0075)(1.0075)^{300}} = 119.1616]

Solution

✅ Correct Option: 2

The loan amount is the home price minus the down payment:

Loan Amount (P) = Rs. 10,00,000 - Rs. 2,00,000

P = Rs. 8,00,000


The interest details are:

Annual Interest Rate = 9% per annum

Monthly Interest Rate (r) = 9% ÷ 12 = 0.75% = 0.0075

Time Period = 25 years = 25 × 12 = 300 months (n)


The EMI formula is:

EMI=P×r(1+r)n(1+r)n−1\text{EMI} = P \times \frac{r(1+r)^n}{(1+r)^n - 1}

Where P = 8,00,000, r = 0.0075, and n = 300


The given expression (1.0075)300−1(0.0075)(1.0075)300=119.1616\frac{(1.0075)^{300} - 1}{(0.0075)(1.0075)^{300}} = 119.1616 is the reciprocal of the term needed in the EMI formula.

Therefore:

(0.0075)(1.0075)300(1.0075)300−1=1119.1616\frac{(0.0075)(1.0075)^{300}}{(1.0075)^{300} - 1} = \frac{1}{119.1616}


Substituting into the EMI formula:

EMI=8,00,000×1119.1616\text{EMI} = 8,00,000 \times \frac{1}{119.1616}

EMI=8,00,000119.1616\text{EMI} = \frac{8,00,000}{119.1616}

EMI=6713.57\text{EMI} = 6713.57

Therefore, the equal monthly installment is Rs. 6713.57

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