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The number of all possible matrices of order 2×32 \times 3 with each entry 0 or 1 is

Solution

✅ Correct Option: 4

A 2×32 \times 3 matrix has 2 rows and 3 columns:

[______]\begin{bmatrix} \_ & \_ & \_ \\ \_ & \_ & \_ \end{bmatrix}

Each blank position can be filled with either 0 or 1.


Total number of entries in the matrix:

2×3=62 \times 3 = 6 entries


For each entry, there are exactly 2 choices: either 0 or 1.

Since each of the 6 entries has 2 independent choices:

Total number of different matrices =2×2×2×2×2×2= 2 \times 2 \times 2 \times 2 \times 2 \times 2

=26= 2^6

=64= 64


For any matrix of order m×nm \times n with each entry having kk choices:

Total matrices =km×n= k^{m \times n}

In this case: 22×3=26=642^{2 \times 3} = 2^6 = 64

Therefore, the answer is 64.

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