Let y = _e (a + b x/a - b x), then value of dy/dx is : Option 1: ab x/a^2 - b^2 ^2 x Option 2: ab x/a^2 + b^2 ^2 x Option 3: a x/a^2 - b^2 ^2 x Option 4: 2ab x/a^2 - b^2 ^2 x

The answer is '2ab x/a^2 - b^2 ^2 x'. View full solution:

CUET Mathematics - Let y = _e (a + b x/a - b x), then value of dy/dx is : | PYQs + Solutions

CUET Mathematics 2023 22 May Shift 3

Calculus

Medium

$\frac{ab \cos x}{a^2 - b^2 \sin^2 x}$

$\frac{ab \cos x}{a^2 + b^2 \sin^2 x}$

$\frac{a \sin x}{a^2 - b^2 \sin^2 x}$

$\frac{2ab \cos x}{a^2 - b^2 \sin^2 x}$

✅ Correct Option: 4

Related questions:

3 June Shift 2

Match List-I with List-II

List-I	List-II
(A) $\int \dfrac{dx}{x^2 - 16}$	(I) $\dfrac{1}{8} \log \left\vert \dfrac{4 + x}{4 - x} \right\vert + c$ , Where C is an arbitrary constant,
(B) $\int \dfrac{dx}{x^2 + 16}$	(II) $\log \left\vert x + \sqrt{x^2 - 16} \right\vert + c$ , Where C is an arbitrary constant,
(C) $\int \dfrac{dx}{16 - x^2}$	(III) $\dfrac{1}{8} \log \left\vert \dfrac{x - 4}{x + 4} \right\vert + c$ , Where C is an arbitrary constant,
(D) $\int \dfrac{dx}{\sqrt{x^2 - 16}}$	(IV) $\dfrac{1}{4} \tan^{-1} \left( \dfrac{x}{4} \right) + c$ , Where C is an arbitrary constant,

Choose the correct answer from the options given below:

21 May Shift 1

The greatest integer function $f(x) = [x]$ is differentiable for all values of

14 May Shift 1

If $y = 3e^{2x} + 2e^{3x}$ , then $\frac{d^2y}{dx^2} + 6y$ is equal to