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if x=atan⁡−1tx=\sqrt{a^{\tan^{-1}t}} and y=acot⁡−1ty=\sqrt{a^{\cot^{-1}t}} then which one of the following is true?

Solution

✅ Correct Option: 2

Multiplying, xy=a12(tan⁡−1t+cot⁡−1t)=aπ/4xy=a^{\frac12(\tan^{-1}t+\cot^{-1}t)}=a^{\pi/4}, a constant. Differentiating xy=xy= constant gives x dy+y dx=0x\,dy+y\,dx=0.

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