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If an investment value get doubled in 10 years then its compound annual growth rate (CAGR) is: (Given 21/10=1.07292^{1/10} = 1.0729)

Solution

✅ Correct Option: 4

The investment doubles in 10 years.

Let the initial value be PP.

Final value =2P= 2P

Time =10= 10 years


Using the compound interest formula:

Final Value == Initial Value ×(1+CAGR)number of years\times (1 + \text{CAGR})^{\text{number of years}}

2P=P×(1+CAGR)102P = P \times (1 + \text{CAGR})^{10}

2=(1+CAGR)102 = (1 + \text{CAGR})^{10}


Taking the 10th root of both sides:

1+CAGR=21/101 + \text{CAGR} = 2^{1/10}

Given that 21/10=1.07292^{1/10} = 1.0729:

1+CAGR=1.07291 + \text{CAGR} = 1.0729

CAGR=1.0729−1\text{CAGR} = 1.0729 - 1

CAGR=0.0729\text{CAGR} = 0.0729


Converting to percentage:

CAGR=0.0729×100\text{CAGR} = 0.0729 \times 100

CAGR=7.29%\text{CAGR} = 7.29\%

Therefore, the compound annual growth rate is 7.29%7.29\%.

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