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A person can sell a maximum of 20 units of shirts and pants on which a profit of ₹40 is made on each shirt and a profit of ₹30 on each pant. A minimum of 2 shirts are being sold, while pants are sold at least 4 times as many as shirts. Then the maximum profit is:

Solution

✅ Correct Option: 3

Let xx = number of shirts and yy = number of pants.

Profit on each shirt = ₹40

Profit on each pant = ₹30

The constraints are:

  • Total items: x+y≤20x + y \leq 20
  • Minimum shirts: x≥2x \geq 2
  • Pants at least 4 times shirts: y≥4xy \geq 4x

Goal: Maximize profit P=40x+30yP = 40x + 30y


Since y≥4xy \geq 4x and x+y≤20x + y \leq 20:

x+4x≤20x + 4x \leq 20

5x≤205x \leq 20

x≤4x \leq 4

Combined with x≥2x \geq 2, the possible values are x∈{2,3,4}x \in \{2, 3, 4\}


For x=2x = 2:

Minimum pants: y≥4(2)=8y \geq 4(2) = 8

Maximum pants: y≤20−2=18y \leq 20 - 2 = 18

Best choice: y=18y = 18

Profit =40(2)+30(18)= 40(2) + 30(18)

=80+540= 80 + 540

=620= 620


For x=3x = 3:

Minimum pants: y≥4(3)=12y \geq 4(3) = 12

Maximum pants: y≤20−3=17y \leq 20 - 3 = 17

Best choice: y=17y = 17

Profit =40(3)+30(17)= 40(3) + 30(17)

=120+510= 120 + 510

=630= 630


For x=4x = 4:

Minimum pants: y≥4(4)=16y \geq 4(4) = 16

Maximum pants: y≤20−4=16y \leq 20 - 4 = 16

Best choice: y=16y = 16

Profit =40(4)+30(16)= 40(4) + 30(16)

=160+480= 160 + 480

=640= 640


The maximum profit is ₹640.

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